【解決方法】 C++ のコードがあるので、それを C プログラムに変換し、flowgorithm のブロックスキームとして変換する必要があります。 誰か助けてくれませんか？

#include <iostream>
using namespace std;
int num(int arr[], int n, int x)
{
    int r = 0;
    for (int i=0; i<n; i++)
    	if (x == arr[i])
          r++;
        return r;
}
 
int main()
{
   
    int m;
    cout<< "Number of elements of array: "<<endl;
    cin>>m;
    int nums[m];
    cout<< "Fill in the array: "<<endl;
    for(int i=0;i<m;i++){
    	cin>>nums[i];
	}
	
    
	int n = sizeof(nums)/sizeof(nums[0]);
    cout << "Array is: ";
    for (int i=0; i < n; i++){
    	cout << nums[i] <<" ";
	}
	cout<<endl;
	int x,elem;
	cout << "Put an element to see how many times is on array: ";
    cin>> x;
    cout <<"\nNumber "<< x <<" is "<< num(nums, n, x)<< " times";
    cout<<"\nPut a new element after the given element: ";
    cin>>elem;
    cout<<"\nNew array is:\n";
    for(int i=0; i<num(nums, n, x); i++){
    	cout <<x<<", "<<elem<<", ";
    }
    cout<<endl;
    return 0;
    }

私が試したこと:

 #include <stdio.h>
#include <conio.h>
int num(int arr[], int n, int x)
{
    int r = 0;
    for (int i=0; i<n; i++)
    	if (x == arr[i])
          r++;
        return r;
}
 
int main()
{
   
    int m;
    printf("Number of elements of array:\n ");
    scanf("%d",&m);
    int nums[m];
     printf("Fill in the array:\n ");
    for(int i=0;i<m;i++){
    	scanf("%d", &nums[i]);
	}
	
	int n = sizeof(nums)/sizeof(nums[0]);
    printf("Array is:\n ");
    for (int i=0; i < n; i++){
    	printf("%d", nums[i]); 	
	}
	int x,elem;
	    printf("Put an element to see how many times is on array:: \n ");
	scanf("%d",&x);
    printf("Number" "%d", x ," is " "%d" , num(nums, n, x) ," times");
    printf("Put a new element after the given element:\n ");
    scanf("%d", &elem);
    printf("New array is:\n ");
    for(int i=0; i<num(nums, n, x); i++){
    	printf("%d", x ,"," "%d", elem ,",");
    }
    printf("\n");
    getch();
    return 0;
    }