API请求信息

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我有一个调用 API 的函数,如下所示
现在,我如何从 wsdlUri 获取我传递的信息,例如 userId 和 memberId

。网
public SyncService1()
        {
            //InitializeComponent();
            siteInfo.AdminLogin = ConfigurationManager.AppSettings["adminID"].ToString();
            siteInfo.AdminPassword = ConfigurationManager.AppSettings["adminPWD"].ToString();
            siteInfo.wsdlUri = ConfigurationManager.AppSettings["uri"].ToString();
            siteInfo.LoggingDirectory = ConfigurationManager.AppSettings["LoggingDirectory"].ToString();
            log.Info($"Logging directory is located in {siteInfo.LoggingDirectory}");
            Console.WriteLine($"Logging directory is located in {siteInfo.LoggingDirectory}");

            // Initialize log4net.
            log4net.Config.XmlConfigurator.Configure();
        }

我期待着
siteInfo.wsdlUri.Userid=`您的文本`
siteInfo.wsdlUri.MemeberId=`您的文本`

我尝试过的:

siteInfo.wsdlUri.Userid=`your text`
siteInfo.wsdlUri.MemeberId=`your text`

解决方案1

您可以使用 System.Uri 类来解析 URI 并提取所需的信息。

C#
siteInfo.wsdlUri = ConfigurationManager.AppSettings["uri"].ToString();
string uri = siteInfo.wsdlUri;
System.Uri parsedUri;

// To validate the URI format
if (Uri.TryCreate(uri, UriKind.Absolute, out parsedUri))
{
	// Here you can use it from query parameters
	siteInfo.wsdlUri.UserId = parsedUri.QueryParameters["UserId"];
	siteInfo.wsdlUri.MemberId = parsedUri.QueryParameters["MemberId"];
}
else
{
	Console.WriteLine("Invalid URI format");
}

如果 URI 不包含查询参数,并且信息以不同的方式编码,则需要相应地调整解析逻辑。

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